#Example 10-2 Catalytic Reactor Design d(X)/d(W)= -rt/FTo FTo = 50 k = .00087 KT = 1.038 KB = 1.39 alpha = 0.000098 Po = 40 PTo = 0.3*Po p = (1-alpha*W)^0.5 P = p*Po PH2 = PTo*(1.5-X)*p # PB = PTo*X*p # PT = PTo*(1-X)*p # rt = -k*PT*PH2/(1+KB*PB+KT*PT) # RATE = -rt # W(0)=0 X(0)=0 W(f)=10000