#Example 4-4: Rate Law for SO2 Oxidation W(0) = 0 W(f) = 1000 d(X) / d(W) = -ra/Fao X(0) = 0 Fao=3 PSO2=PSO20* (1-X)/(1+epsilon*X) PSO3=PSO20* X/(1+epsilon* X) PO2=PSO20* (thetaB-X/2)/(1+epsilon* X) ra=-k *(PSO2* Sqrt(PO2)-PSO3/KP)/(1+Sqrt(PO2* KO2)+PSO3 *KSO3)^2 thetaB=0.54 epsilon=-0.14 k=9.7 KO2=38.5 KSO3=42.5 KP=930 PSO20=4.1 yaxis=Fao/(-ra)